C++ Institute CLA-11-03 Dumps Questions Answers

The main function declares an integer i and initializes it to 1. Then, it enters a for loop with no initialization statement, a condition i > 128, and an iteration expression i *= 2. The loop will continue to execute as long as i is greater than 128, but since i starts at 1, the loop's condition is false right from the start, meaning the loop body never executes.

However, this looks like an oversight, because usually, with this kind of loop, the intention is to run the loop until the condition becomes false. If the condition were i < 128, i would double each iteration until it reached or exceeded 128.

Given the current condition i > 128, the loop does nothing, and printf will output the ini-tial value of i, which is 1.

1.A function fun is defined that takes a pointer to an integer t and returns t + 4.

2.The main function defines an array arr with the elements { 4, 3, 2, 1, 0 }.

3.It then calls fun with the argument arr - 3. Since arr points to the first element of the array, arr - 3 is actually pointing to 3 positions before the start of the array, which is out of bounds.

4.Inside fun, t + 4 would effectively be arr + 1 (arr - 3 + 4).

5.The returned pointer from fun (which is arr + 1) is assigned to ptr.

6.ptr[2] is then the same as arr[1 + 2], which is arr[3]. The value at arr[3] is 1.

This is the correct way to declare a pointer to an array of 10 int values. The parentheses are necessary to indicate that p is a pointer to an array, not an array of pointers. The base type of p is ‘an array of 10 int values’.12 References = 1: Pointer to an Array | Array Pointer - GeeksforGeeks 2: What is a pointer to array, int (*ptr) [10], and how does it work? - Stack Overflow